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From: ------
In the most basic terms, if you don't have any loss to ambient, the heat rate you put into your exchanger must be what is coming out. m(h2-h1)=m*(h1*-h2*) where m=mass flow rate of fluid 1 in lbm/hr h1=enthalpy of fluid 1 at inlet in btu/lbm h2=enthalpy of fluid 1 at outlet in btu/lbm *=fluid2
The more lbm/hr you can push generally increases your heat xfer. There are more complicated formulie when you get into the counter-flow, once-through, twice through, etc.
Hope this helps.