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Re: Flat latout for sheet metal rolled radially formula needed.

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Posted By<" ">William on September 12, 2002 at 19:00:35:

In Reply to: Flat latout for sheet metal rolled radially formula needed. posted byRalph Rivers on September 12, 2002 at 16:47:36:

: I have a rolled aluminum sheet metal with a 30.18" radius and have cutouts in it. Is there a formula that anyone can provide for calculating the length of the curves into a flat layout so that we can pre-cut this flat then roll-it?

The formula for features up to 180 degrees is
o.o1745 (times) radius (times) angle in degrees.
For your flat length of the circle (circumfrence)be sure to use the mean diameter. That is the finshed OD you want to end up with minus 1/2 the material thickness x2 (or minus the material thickness once). If you do use the OD to figure the circumfrence, you will come out too big every time. In your case; if the material is say 1/2" thick and you want the actual OD to be 60.36. The mean dia is 59.86" x pi(3.1415)=188.055" or 15 feet 8 inches long in the flat. Butt weld the ends.

Good luck

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Subject: Re: Re: Flat latout for sheet metal rolled radially formula needed.

Comments:: : I have a rolled aluminum sheet metal with a 30.18" radius and have cutouts in it. Is there a formula that anyone can provide for calculating the length of the curves into a flat layout so that we can pre-cut this flat then roll-it? : The formula for features up to 180 degrees is : o.o1745 (times) radius (times) angle in degrees. : For your flat length of the circle (circumfrence)be sure to use the mean diameter. That is the finshed OD you want to end up with minus 1/2 the material thickness x2 (or minus the material thickness once). If you do use the OD to figure the circumfrence, you will come out too big every time. In your case; if the material is say 1/2" thick and you want the actual OD to be 60.36. The mean dia is 59.86" x pi(3.1415)=188.055" or 15 feet 8 inches long in the flat. Butt weld the ends. : Good luck :

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