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Starting & Rolling Resistance | |||
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Posted by: ABURNS ® 12/17/2005, 07:02:36 Author Profile Mail author Edit |
I am currently working on designing a mobile Pneumatic test rig and need to calculate the force required to initially get the rig rolling and the force thereafter to keep it in motion, the weight of the rig is 250kg and is supported on 4-off 100mm dia. nylon casters............can anyone help?!! |
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Re: Starting & Rolling Resistance | |||
Re: Starting & Rolling Resistance -- ABURNS | Post Reply | Top of thread | Forum |
Posted by: zekeman ® 12/18/2005, 21:30:59 Author Profile Mail author Edit |
Your main contributor of force is the acceleration you need to get to speed. Your rolling friction is negligible. Only bearing friction of the wheels and gearbox conribute, also small by comparison. If you actually need it , you must specify the bearing
design and gearbox design. The force due to the acceleration is weight/32*acceleration. For uniform acceleration,A A=(final speed)/(time to get to speed) |
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Re: Starting & Rolling Resistance | |||
Re: Re: Starting & Rolling Resistance -- zekeman | Post Reply | Top of thread | Forum |
Posted by: zekeman ® 12/18/2005, 21:40:49 Author Profile Mail author Edit |
Correction for units. I correctly gave it in the old English system where
force is in lbs, weight in lbs and acceleration is in ft/sec^2; if you use MKS sys, then force (Newtons) = mass (KG)*acceleration (meters/sec^2) |
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