Posted by: Aztek ® 07/14/2006, 04:48:47 Author Profile eMail author Edit

Hello, it is known that bearing stress is calculated by dividing the load by the area of the rectangle representing the projection of the bolts on the plate section. That is, the load (P) is divided by the thickness of the plate (t) times the diameter of the bolt (d)....S=P/(td) In the application of countersunk bolts, how does this calculation change in the countersunk part of the plate? Should I take the projection of the area from drawing programs? Thank you! Mechanical Engineer M.Sc

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Re: Countersunk Bolts, Bearing Stress
Re: Countersunk Bolts, Bearing Stress -- Aztek	Post Reply	Top of thread	Forum

Posted by: stewart ® 07/14/2006, 07:54:13 Author Profile eMail author Edit

Hello Is this a flathead screw? Is the head in the shear plane? Stewart

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Re: Re: Countersunk Bolts, Bearing Stress
Re: Re: Countersunk Bolts, Bearing Stress -- stewart	Post Reply	Top of thread	Forum

Posted by: Aztek ® 07/14/2006, 08:49:49 Author Profile eMail author Edit

Thank you for your response, The head is flat (DIN 7991) and the shear plane is not on the head section but under the effect of shear load, the head section try to apply pressure to the upper plate.... Now the projected area is not t times d. In fact it is larger but what amount? Mechanical Engineer M.Sc

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Re: Re: Re: Countersunk Bolts, Bearing Stress
Re: Re: Re: Countersunk Bolts, Bearing Stress -- Aztek	Post Reply	Top of thread	Forum

Posted by: stewart ® 07/18/2006, 20:31:25 Author Profile eMail author Edit

Hello Aztek I am sorry I cannot be of more help. Stewart

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