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TIR on rolls | |||
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Posted by: strataballer02 ® 07/19/2006, 20:48:25 Author Profile eMail author Edit |
I am trying to wrap my head around this TIR problem. Picture a roll sitting on a pedestal. One support is at 3 o'clock, the other at six o'clock. Now check the TIR with a dial indicator at 12 o'clock. Let's say you get .002" or .004" or anything you can make up. Now put the indicator at 9 o'clock, it reads zero runout. How does this occur? |
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Re: TIR on rolls | |||
Re: TIR on rolls -- strataballer02 | Post Reply | Top of thread | Forum |
Posted by: randykimball ® 07/19/2006, 22:58:46 Author Profile eMail author Edit |
Let's play with our mind eyes for a second... In your mind place the supports at 5 o'clock and 7 o'clock. Now place the indicator at 12 o'clock. Now look for the TIR.
Also, placing the shaft on a support and indicating the roll should show roundness IF the shaft is straight and round. As I understand in your example the support at 3 o'clock is only there to keep the roll centered under the indicator. I asume you are placing the indicator on a shaft at the end of the roll or in a bore... or have the shaft on supports and are checking the top of the roll, ...this would be the TIR of the two diameters (shaft to roll diameter). You should check for roundness. I prefer the 5 o'clock and 7 o'clock positions.. notice that a shaft balancer uses aprox 5:30 and 6:30. Geeze.. is that muddy enough? There are several factors at play here. The worst suggestion of your lifetime may be the catalyst to the grandest idea of the century, never let suggestions go unsaid nor fail to listen to them. Modified by randykimball at Wed, Jul 19, 2006, 23:59:49 |
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