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| Fluids Problem (Jet Flow) | |||
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| Posted by: blakes30 ® 11/07/2006, 09:20:43 Author Profile eMail author Edit |
If we have a tank of water and a hole or nozzle somewhere at a distance h1 from the top surface, the velocity of the water leaving the tank is v = √(2gh1). This is "Toricelli's Theorem" Question: Ignoring friction losses, Let's say that the pipe runs out from this same distance but turns up and extends upward at a height h2. Now, what is the velocity discharging from the tank? Would it still be v = √(2gh1) or would it now be v = √(2g(h1-h2))? In other words, how would we account for the pipe that extends upward a distance of h2? (remember--ignore friction losses in the pipe). |
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| Re: Fluids Problem (Jet Flow) -- blakes30 | Post Reply | Top of thread | Forum |
| Posted by: swearingen ® 11/08/2006, 08:14:07 Author Profile eMail author Edit |
Remember how you defined h1? It's the distance from the top surface to the nozzle. When you go up h2, you've just reduced your original h1 by a distance h2. My take is that you now have a new, shorter, h1 and you use the same equation with this new h1. As you say, though, the new h1 equals the old h1 minus h2. |
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