applying torsion to a bar made from 4130 material - Please help
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Posted by: Bkelly301 ®

01/25/2007, 13:23:39

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Hi, I'm new to this forum. I was just wondering if anyone can help me out in solving a problem. A friend of mine from work is building a hot rod, and he wants to add a torsion bar (I think that's what it is called). It's actually a piece of tubing. Anyway, he asked me the following question:

"If I have a piece of tubing made from 4130 material, and I apply a torsion force to it at one end (the other end is fixed) would it return back to it's orignal shape?"

I did some google searches on torsion, torque, moments, stresses, elasticity, etc.... But I was unable to find out how to go about figuring this problem out. The only thing I found was an equation for torsional resilience, which is denoted as 'U'. The equation is U = Ø^2GIp/2L, where G is the shear modulus, Ip is the polar moment of inertia, Ø is the angle of twist, and L is the length of the tube. I have all the information I need to solve this equation, and I figured that at a given angle Ø, if U is greater then the applied torsion, then the tubing will 'spring' back to its original shape. However, when I tried to solve it, the numbers were not making sense. I have a feeling that this is not the right way to solve this problem. So if anyone can help me or point me in the right direction as to how to go about solving this problem, I would greatly appreciate it. Thanks in advance.








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