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| boiler sizing |  | ||
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| Posted by: silas ® 05/26/2009, 07:13:23 Author Profile eMail author Edit |
I have an application that requires: 36m3 of 93c water an hour, the system will be at max 3bar can anyone tell me how to work the boiler size required for this? Modified by silas at Tue, May 26, 2009, 08:38:39 |
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Posted by: devitg ®  05/31/2009, 06:47:26 Author Profile eMail author Edit |
What is the incoming temp of water Heat load = flow x especific heat x delta T
delta t = out temp - in temp Modified by devitg at Sun, May 31, 2009, 06:48:02 |
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| Posted by: silas ® 06/01/2009, 02:47:48 Author Profile eMail author Edit |
boiler feed/return water at 80c |
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| Posted by: devitg ® 06/01/2009, 15:00:13 Author Profile eMail author Edit |
You need 32000 liter/hr * 1 * (93 - 80 ) = 416000 cal/hr / 80 % effiecience = 520000 Cal / Hr
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| Posted by: silas ® 06/01/2009, 16:01:08 Author Profile eMail author Edit |
Sorry if I am being a bit stupid here but 520000 cal/hr is only .6kw/h have i misunderstood your answer? |
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| Posted by: devitg ® 06/01/2009, 19:57:51 Author Profile eMail author Edit |
By definition 1 cal , is the heat to rise 1 gram of water from 20° C to 21°C
And 1Cal is the heat to rise 1000 Grams or 1 Kg Sorry , i missplaced the units. It is 520000 Cal/hr or also call Grand calorie , also it is named Kcal So for 32000 liter , or Kg , not taking in count the specific volumen by delta-t= 93-80= 13 degree
the Kcal to Kw . 1 Kw = 860 Kcal Sorry againg, if I did a misstake.
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